Exercise set 4
The symbol G denotes a finite group. The character of a finite dimensional (complex) representation V is
denoted by
V .
-
(1)
- (Difficulty level: 1) Convince yourself of the following:
- Hom(V,W) ≃ V *⊗ W
V ⊕W =
V +
W
V ⊗W =
V
W
V * =
V
Hom(V,W) =
V
W
-
(2)
- (Difficulty level: 3) Calculate character tables of the symmetric groups on 3, 4, and 5 letters; of
cyclic groups; of the dihedral groups; of the non-cyclic group of order 4; of all groups of order 8;
of all groups up to order 12; etc.
-
(3)
- (Difficulty level: 2) Deduce the following from Wedderburn’s structure theorem, where R denotes a
finite dimensional semisimple algebra over an algebraically closed field k:
- (a criterion for simplicity) R is simple if and only if it admits a unique simple module.
- (density) If V 1, …, V k are pairwise non-isomorphic simple R-modules, and φ1, …, φk
are arbitrarily specified k-linear transformations, then there exists r in R which acts
on V i like φi for all 1 ≤ i ≤ k.
- (”left semisimplicity and right semisimplicity are equivalent”) R is semisimple as a
right module.
Additional problems (Optional)
-
(1)
- (Burnside’s lemma) Let k be an algebraically closed field. Let R be a k-algebra (not
necessarily finite dimensional) and let V be a finite dimensional simple R-module. Show
that R → EndkV (the map defining V as an R-module) is surjective. (Hint: Let the image of
R in EndkV be denoted by S. Note that V is a simple module for S. Since EndkV = V ⊕
⊕ V
(dimkV times) as a EndkV module, it follows that it is semisimple as an S-module. Thus S is
semisimple as a module over itself (being a submodule of a semisimple module), which means that
S is a semisimple algebra. Since V is a simple module for S, it follows from Wedderburn that
dimkS ≥ (dimkV )2. Thus S = EndkV . □)
-
(2)
- Let k be an algebraically closed field. Show that any finite dimensional simple k-algebra
is isomorphic to the matrix ring Mn(k) for some n. (Hint: Let R be such an algebra. By
definition, R≠0. Choose a simple module V for R and consider R → EndkV defining V as an
R-module (note that V exists). This map is surjective by Burnside’s lemma (previous item) and
injective because R is simple. □)