Exercise set 2.2

Throughout, K denotes a field and V a vector space over K of finite dimension d 1. We fix an integer m 1 and denote by G the group GLK(m). We denote by AK(m) the ring of polynomial functions on G and by SK(m) and SK(m,n) the appropriate Schur algebras (as defined in the lecture).

(1)
(Difficulty level 1) Let U and W be finite dimensional K-vector spaces. Convince yourself that the following are equivalent for a (set) map φ : U W:
(a)
There exists a basis {wi} of W such that the K-valued functions φi on U defined by φ(u) = iφi(u)wi are all polynomial.
(b)
For any basis {wi} of W, the K-valued functions φi on U defined by φ(u) = iφi(u)wi are all polynomial.
(c)
For any linear functional ζ on W, the K-valued function ζ φ on U is polynomial.
(d)
For any polynomial function f on W, the K-valued function f φ on U is polynomial.

If any of these holds, then φ is said to be a polynomial map from U to W.

(2)
(Difficulty level 2) Let ρ : G GL(V ) be a polynomial representation and ρ: G GL(V *) the contragredient representation of ρ. Observe that g↦→ρ(g)-1 is a polynomial map from G to EndKV * (although not a group homomorphism, but only an anti-homomorphism).
(3)
(Difficulty level 1) Verify that SK(m,1) is isomorphic to the matrix algebra Mm(K).
(4)
(Difficulty level 2) For α in SK(m), let αn denote its projection to SK(m). (Recall that this projection is induced from the inclusion of homogeneous polynomials of degree n in the ring AK(m).) We think of α↦→αn as a map from SK(m) to SK(m), considering αn to be an element of SK(m) under the inclusion of SK(m,n) SK(m). (Recall that this inclusion is induced by the projection of AK(m) onto its homogeneous component of degree n.) Show that δI,n (where I stands for the identity element of G, the m×m identity matrix), as n varies over the non-negative integers, are pairwise orthogonal central idempotents. (Caution: they are not primitive central idempotents, except in very special cases, as we will see.)
(5)
(Difficulty level 3) We now outline a proof of the fact that a (finite dimensional) polynomial SK(m)-module arises from a polynomial representation of G. More precisely, we show that any polynomial SK(m)-module ˜ρ : SK(m) EndK(V ) that is homogeneous of degree n arises from a homogeneous polynomial representation ρ : G GL(V ) of G of degree n. The candidate for ρ is clear: ρ(x) := ˜ρ (δx) for x in G. It is also clear that ρ is a representation since δxy = δx ⋆ δy). It remains only to prove that ξ,ρ(g)vis a polynomial function of g, as g varies over G (for any fixed v in V and ξ in V *).

Since SK(m,n) is the dual of the finite dimensional K-vector space AK(m,n), it is clear that there exists a homogeneous polynomial cξ,v in AK(m,n) such that

           ∫
⟨ξ,ρ˜(αn)v⟩ =   cξ,v(x)dαn(x)  for all αn in SK (m, n).

Since v = ˜ρ (δI,n)v, it follows that

˜ρ(α)v = ˜ρ(α )(˜ρ(δI,n)v) = ˜ρ(α⋆ δI,n)v = ˜ρ(αn)v for all α in SK (m).

On the other hand, since cξ,v is homogeneous of degree n, we have

∫            ∫

  cξ,vdα (x) =   cξ,vdαn(x)  for all α in SK(m ).

From the equations in the last three displays, we conclude that

           ∫
⟨ξ,˜ρ(α)v⟩ =  cξ,v(x)dα(x)  for all α in SK(m ).

Putting α = δg, we obtain ξ,ρ(g)v= cξ,v(g).