of k into the field of complex numbers
, the
valued points of X 

form
a complex manifold denoted by X
. By base change for the de Rham cohomology
HDRj(X/k)

= HDRj(X

/
) and by the GAGA principle one has an isomorphism I
from HDRj(X/k)

to the Betti cohomology HBj(X
,
) ([5], p. 96).
Chow group CHi(X) 

has a de Rham class

: k 

is an absolute Hodge cycle, a notion defined by Deligne [3], §2, which we slightly
modify, as we are only interested here in de Rham cohomology (see [3], open question
2.2).
Definition 1 A class
FiH
DR2i(X/k) is said to be an absolute Hodge cycle if for all
embeddings
: k 
, I
(
) lies in HB2i(X
,
).
On the other hand, such an algebraic cycle has an absolute de Rham class in
2i(X,
X/
>i). In
fact, there is an absolute differential
![dlog : O*X ----> _O_ >X1/Q [1]](ln2x.png)
![M >i
dlog : K i ----> _O_X/Q [i]](ln3x.png)


= Hi(X,K
iM) ([9],
théorème 5), d log induces the absolute de Rham cycle class map



= FiH
DR2i(X

/
), so it is enough to handle
k =
, in which case the compatibility is proven in [2], (2.2.5.1) and (2.2.5.2) for i = 1. For
i > 1, resolving the structure sheaf of an effective cycle by vector bundles, and for a given vector
bundle, computing its Chern classes on the Grassmannian bundle G
- -
X, with
* : FiH
DR2i(X/
)
FiH
DR2i(G/
), one reduces the compatibility to the case
i = 1.
Remark 2 The existence of the absolute de Rham cycle class is proven in great generality in
[10] when X is singular. In fact, this class is convenient to formulate some questions. For
example, its injectivity for a surface X over k =
would imply Bloch’s conjecture when
H2(X,O
X) = 0.
At any rate, the existence of
motivates the following
Definition 3 A class
FiH
DR2i(X/k) is said to be an absolute de Rham cycle if it lies in the
image of HDR2i(X/
) in
DR2i(X/k).
We denote by
: HDRj(X/k)
k/
1
kHDRj(X/k) the Gauss-Manin connection for the
smooth morphism X
Spec k of schemes over Spec
.

Proof. The sequence is obviously a complex.
Let k0
k be the field of definition of X. One has X = X0
k0k, where X0 is smooth proper
over k0, and k0 =
(S0) for a smooth affine variety S0 over
, such that there is a smooth
proper map f0 : X0
S0 with X0
OS
0k0 = X0.
As HDRj(X
0/k0) is a finite dimensional k0 vector space, any

k0
(S), where k0 
(S)
k and S is a smooth affine variety mapping to
S0. If x
Ker
, then x lies in the kernel of


S the smooth proper morphism obtained by base change
S
S0 of f0. Making S smaller, one may assume that there is

OS
(S) =
, and one wants to show that
Im HDRj(X/
).
X/
• one considers the filtration by the subcomplexes f*
S/
>a
X/
•-a. It defines a
spectral sequence

), whose d
1 differential is the Gauss-Manin connection
. As S is
affine, one has



)an, Xan = (X

)an. The corresponding
spectral sequence

a+b(X
an,
Xan•) = Ha+b(X
an,
). This spectral sequence is, according to
Deligne ([11], (2.77) and (15.6)) the Leray spectral sequence, and by [2], (4.1.1) (i), it
degenerates at E2.



degenerates at E2, and so does (E1ab,d
1). In particular

(S).
Remark 5 In fact, even if S is not affine, there is a Leray spectral sequence for the de Rham cohomology [7] (3.3), which again degenerates at E2 by the comparison between the Leray spectral sequences for the Betti and the de Rham cohomologiesi, and the regularity of Gauss-Manin. For more on this, see [8].
Corollary 6 If
is an absolute Hodge cycle, then it is an absolute de Rham cycle.
Proof. By [3] (2.5), we know that 
= 0, where
is as in (4) for j = 2i. Then we apply
(4).
Corollary 7 If
is an absolute de Rham cycle such that I
(
)
HB2i(X
,
) for some
embedding
: k 
, then
is an absolute Hodge cycle.
Proof. In fact, this is [3] (2.6). More precisely, choose S as in the proof of 4 and
HDR2i(X/S) restricting to
. The embeddings
(S)
k
- - 
define a
valued point of
S, which we still denote by
, such that
(
)
H2i((X
an)
,
)
H2i((X
an)
,
). The image
(
) of
in


|(Xan)s is rational for all s, in particular for those s coming from an embedding
: k 
.
Remark 8 An advantage, if any, to adopt the language of absolute de Rham cycles consists of
dividing the question of wether
is absolute Hodge or not into two steps:
First of all
must be in

must be in

On the other hand, we have seen that if
FiH
DR2i(X/k) is the class of an algebraic cycle,
then not only it is an absolute de Rham cycle, but also it is coming from
2i(X,
X/
>i).
Let f : X
S,
FiH
DRj(X/S) = H0(S,Rjf
*
X/S>i), such that

(S)k =
FiH
DRj(X/k)
as in the proof of 4. Let f
: X
S
be the smooth proper morphism obtained from f by
base change OS 

, and 
be


. Let f
: X
S
be a compactification of
f
such that
= S
- S
, D = f
-1(
) are normal crossing divisors and X
is
smooth.
Definition 9 A class
FiH
DRj(X/k) is said to be of moderate growth if for some (
,f
) as
above, it verifies

Remark 10 The definition 9 does not depend on the couple (
,f
) choosen. In fact, take (
,g)
with g : Y
T,
(T)
k, Y
(T)k = X,

(T)k =
. Then considering in k a function
field
(U) containing
(S) and
(T), one has base changes
: U
S,
: U
T,
fU : XU = X×SU
U, gU : YU = Y×T U
U, such that there is an isomorphism
: XU
YU, with gU o
= fU,
*(
OTOU) =
OSOU, for U small enough. As 
fulfills
(*) on S
, it fulfills (*) on any blow up 
: U
S
such that a commutative diagram
exists


-1
,
= f
U,
-1
-1
are normal crossing divisors, X
U,
and U
are smooth. Choose U
such that
extends to 
: U
T
, with a commutative
diagram


This implies in particular that classes of moderate growth build a k subvectorspace of FiH DRj(X/k).
Notation 11 We denote this subvectorspace by FiH
DRj(X,k)log, and by
j(X,
X/
>i)log its
inverse image in
j(X,
X/
>i).

Proof. We have to prove that if
Ker
, then it lies in the image of
j(X,
X/
>i). With the
notations as above,

j(X
,
X
/S
>i(log D)) and
defined as in [7] (3.3) on the complex
X
/S
>i(log D). One has


*
) by [1] II, §6.
Thus the spectral sequence degenerates at E2, and 
comes from
j(X
,
X
>i(log D)). In
particular 
comes from
j(X,
X/
>i) 

and the image of
in

lies in the image of
j(X,
X/
>i).
Remark 13 If the transcendence degree of k is < 1, then of course the sequence

More generally, one can consider a k subvectorspace V of HDRj(X/k), such that I
(V 

) is
a Hodge substructure of HDRj(X
,
). In the light of the above results, one can examine the
following questions.
Question 14 Is V stable under the Gauss-Manin connection?
For this, one would like I
-1[I
(V 

)
HBj(X
,
)] to lie in V and to be independent of
.
If so, then V defines a vector bundle W with a flat connection on S, where S is defined as in 4
such that V = W 
(S)k, W
HDRj(X
0/k0)
k0
(S). Then Wan on San is generated by a
local system F.
Question 15 In the above situation, is the monodromy representation associated to F defined
over
?
Again, one can split up 14 into two parts as in 8. Moreover, the knowledge of 14 does not imply the knowledge of 15.
[1] Deligne, P.: Equations différentielles à points réguliers, Springer LN 169 (1970)
[2] Deligne, P.: Théorie de Hodge II, Publ. Math. de l’IHES 40 (1971), 5 - 58
[3] Deligne, P.: Hodge cycles on abelian varieties, in Hodge cycles, Motives and Shimura Varieties, Springer LN 900 (1982), 9 - 101
[4] Deligne, P.; Illusie, L.: Relèvements modulo p2 et décomposition du complexe de de Rham, Invent. math. 89 (1987), 247 - 270
[5] Grothendieck, A.: On the de Rham cohomology of algebraic varieties, Publ. Math. de l’IHES 29 (1966), 95 - 103
[6] Illusie, L.: Réduction semi-stable et décomposition de complexes de de Rham à coefficients, Duke Math. Journal 60, n01 (1990), 139 - 185
[7] Katz, N.: Nilpotent connections and the monodromy theorem: applications of a result of Turrittin, Publ. Math. de l’IHES 39 (1970), 175 - 232
[8] Paranjape, K.: Leray spectral sequence for de Rham cohomology, preprint
[9] Soulé, C.: Opérations en K-théorie algébrique, Canad. J. of Math. 37 n03 (1985), 488 - 550
[10] Srinivas, V.: Gysin maps and cycle classes for Hodge cohomology, preprint
[11] Zucker, S.: Hodge theory with degenerating coefficients: L2 cohomology in the Poincaré metric, Annals of Math. 109 (1979), 415 - 476